Featured image courtesy of Zimbio.com (Oct. 27, 2018 – Source: Sean M. Haffey/Getty Images North America)
The Boston Red Sox have officially made their first move of the off-season by signing the reigning World Series MVP. According to Jeff Passan of Yahoo Sports, the Red Sox and first baseman Steve Pearce have agreed to a one-year, $6.25 million dollar contract.
Source: Steve Pearce and the Boston Red sox have agreed on a one-year, $6.25M deal.
— Jeff Passan (@JeffPassan) November 16, 2018
Steve Pearce Signs With Red Sox
The Red Sox initially acquired Steve Pearce back in late June in exchange for infield prospect Santiago Espinal. Initially signed to platoon with Mitch Moreland at first base, Pearce was everything the Red Sox could have hoped for, and more.
Pearce stepped up to the plate 165 times as a Red Sox, recording a .279/.394/.507 slash line with a corresponding 143 wRC+. When in the lineup, he was one of the best bats, especially against the New York Yankees. Pearce established himself as a certified Yankee killer during 2018, posting a .333/.448/1.000 slash line with a 269 wRC+ against the Bronx Bombers. Pearce did all this while providing strong defense at first, but he saved his best work for the postseason.
Pearce made quite a few big plays during the Red Sox postseason run, but he saved his best work for the World Series. Playing in all five World Series games, Pearce went 4-12, hitting three home runs and drawing an additional four walks. All three of his home runs came in the last two games of the World Series and all three came in pivotal moments of said games. Pearce’s heroic led to his taking home a well-deserved World Series MVP award.
Pearce will likely enter the season playing a similar role as he did in 2018. Pearce can hit both righties and lefties but is better against lefties. Contrarily, Mitch Moreland is significantly better at the plate against right-handed. Together, these two should form a solid duo for the 2019 Red Sox, although both will be free agents after the 2019 season.