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Red Sox get walked-off by Indians for second straight night

Red Sox
Featured image courtesy of Zimbio.com: (Sept. 22, 2018 РSource: Jason Miller/Getty Images North America)

The Cleveland Indians defeated the Boston Red Sox 4-3 on Sunday night in walk-off fashion on a Greg Allen single in the bottom of the 11th. With the loss, Boston falls to 105-51 while Cleveland propels to 87-68 with the win. Hector Velazquez was the starter for the Red Sox and Adam Plutko did the same for the Indians. The game was played at Progressive Field in Cleveland, Ohio.

After losing in heartbreaking, walk-off fashion the night before, Boston was treated to much of the same as the primetime game of the week. With one out in the bottom 11th, Red Sox killer Allen came to the plate and took a Robby Scott changeup to left field to score Jose Ramirez from third. This at-bat was preceded by an intentional walk to Yandy Diaz.

Ultimately, it was not Scott who got the loss but William Cuevas. Even so, Cuevas was phenomenal in relief duty. He pitched 5 and 1/3 innings, essentially a whole start’s length, of one earned run ball, striking out four and walking three. Cuevas logged more innings than the team’s starter, as Velazquez went 3 and 1/3 innings of two earned run baseball.

On the offensive side, Mookie Betts (surprise!) had a huge night going 4-6 with a homer and a double. His 31st jack was to center field  came in the top 5th to tie the game 3-3.

Another interesting development was Xander Bogaerts being removed from the game with left shoulder soreness. It seemed to just be a precaution and the shortstop is listed as day-to-day.

The Boston Red Sox get ready for their next to last 2018 regular season series against the lowly Baltimore Orioles. Game one of three will be played tonight at 7:10 p.m. eastern. Nathan Eovaldi will be the starter for the Sox and Dylan Bundy will do the honor for the O’s.

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