Indians squash Red Sox comeback attempt, win 5-4
Featured image courtesy of Zimbio.com: (Aug. 19, 2018 – Source: Adam Glanzman/Getty Images North America)
The Cleveland Indians defeated the Boston Red Sox 5-4 on Monday night. With the victory, Cleveland propels to 72-52 and the Red Sox fall to 88-38 with the loss. Rick Porcello was the starter for Boston while Corey Kluber did the same for Cleveland. The game was played at Fenway Park in Boston.
It started off promising for the Red Sox, which scored three runs in the first two innings of the game. Against reigning Cy Young award winner Corey Kluber, that is no easy feat.
Rick Porcello also dominated early and, as the game entered the 5th inning, the Sox led 3-0. After that, a string of Indians’ homeruns ensued. The team hit a homer in the 5th (solo), 6th (two-run) and 7th (two-run). Porcello was responsible for all of the long balls, leaving the game with seven innings of five earned run baseball.
The drama picked up again in the bottom 9th when Mookie Betts began the inning with a leadoff double. Soon after, Andrew Benintendi drew a full-count walk, taking advantage of the clearly flustered Cody Allen. The Indians closer managed to buckle down, though, and retired Mitch Moreland and J.D. Martinez on weakly hit balls.
Up next, Xander Bogaerts hit a weak infield single, which scored a run for Boston. It was 5-4 with Ian Kinsler at the plate and the relatively new addition could not capitalize. He flew out to shallow left field and the game ended.
The Boston Red Sox take on the Cleveland Indians at 7:10 p.m. eastern Tuesday night. Boston will throw out Nathan Eovaldi to make his 5th start for the Sox while Cleveland will turn to rookie Shane Bieber. It will be the second contest of the four-game set.